Westerwolde
New member
- Joined
- Mar 22, 2017
- Messages
- 2
Hello,
A non prismatic figure / beam I need to derive a formula for b (x).
See the picture in the link below:
https://myalbum.com/album/Qs5BcjTUrEdt
The beam has a varying cross-section.
It is given that the dimensions at the end of the beam is determined by the relationship:
b (l) = αb (0), with α less than or equal to 1.
asked:
lead a formula for the dimension b (x) at a distance x from the left bearing.
My book gives answers:
b(x) = b(l) + ((l-x)/l)* (b(0)-b(l))
I self must step by step show the derivation of the function.
How do I do that ?
A non prismatic figure / beam I need to derive a formula for b (x).
See the picture in the link below:
https://myalbum.com/album/Qs5BcjTUrEdt
The beam has a varying cross-section.
It is given that the dimensions at the end of the beam is determined by the relationship:
b (l) = αb (0), with α less than or equal to 1.
asked:
lead a formula for the dimension b (x) at a distance x from the left bearing.
My book gives answers:
b(x) = b(l) + ((l-x)/l)* (b(0)-b(l))
I self must step by step show the derivation of the function.
How do I do that ?