Derivative

Loki123

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Sep 22, 2021
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790
We have what y is (first line). We are supposed to calculate the expression under it (second line). It gets too complicated. Is there a trick? IMG_20220420_111840.jpg
 
We have what y is (first line). We are supposed to calculate the expression under it (second line). It gets too complicated. Is there a trick? View attachment 32257
Now just use those y' and y" and evaluate the given expression. It is a dreary calculation but doable.

Do you have the expected answer?
 
We have what y is (first line). We are supposed to calculate the expression under it (second line). It gets too complicated. Is there a trick? View attachment 32257
Let [imath]f(x)=x\quad \&\quad g(x)=\sqrt{x^2+1}[/imath]
[math] y=(f+g)^n\\ y'=n (f+g)^{n-1}(f'+g')\\ \tag{Product rule} y''=n(n-1)(f+g)^{n-2}(f'+g')(f'+g')+n (f+g)^{n-1}(f''+g'') [/math]Find [imath]f', f'',g', g''[/imath],plug in and simplify.
 
No, the last line is horribly wrong.

Basically you are saying that if 9*0=0, then 9 = 0. NO! 9=9, 9 does not equal 0!
 
I'm sorry but there is too must work to look through. Please try using a website that will just give you the answer. I hope that you understand. I might miss something that you did wrong. Also getting 0 probably means that you are correct.
 
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