Apprentice123
New member
- Joined
- Sep 2, 2008
- Messages
- 22
Doubts with the response
To determine the equation of the sphere that passes in A and B, and has straight center in s
\(\displaystyle A(0,4,3)\) \(\displaystyle B(1,1,-5)\)
(s):
\(\displaystyle x=z+2\)
\(\displaystyle y=z-3\)
My solution:
For the straight, center: \(\displaystyle C(1,1,1)\)
\(\displaystyle R=d(C,A)=\sqrt{14}\)
The equation is:
\(\displaystyle (x-1)^2+(y-1)^2+(z-1)^2=14\)
BUT THE ANSWER IS:
\(\displaystyle (x-3)^2+(y+2)^2+(z-1)^2=49\)
To determine the equation of the sphere that passes in A and B, and has straight center in s
\(\displaystyle A(0,4,3)\) \(\displaystyle B(1,1,-5)\)
(s):
\(\displaystyle x=z+2\)
\(\displaystyle y=z-3\)
My solution:
For the straight, center: \(\displaystyle C(1,1,1)\)
\(\displaystyle R=d(C,A)=\sqrt{14}\)
The equation is:
\(\displaystyle (x-1)^2+(y-1)^2+(z-1)^2=14\)
BUT THE ANSWER IS:
\(\displaystyle (x-3)^2+(y+2)^2+(z-1)^2=49\)
