Find y″ by implicit differentiation. 2x^3 − 3y^3 = 5 y'' =
D Danie;l New member Joined Nov 10, 2020 Messages 7 Nov 10, 2020 #1 Find y″ by implicit differentiation. 2x^3 − 3y^3 = 5 y'' =
skeeter Elite Member Joined Dec 15, 2005 Messages 3,216 Nov 10, 2020 #2 see if you can start by finding y'
topsquark Senior Member Joined Aug 27, 2012 Messages 2,370 Nov 10, 2020 #3 Another hint. y = y(x) so when you find [math]\dfrac{d}{dx} (y^3)[/math] you will need the chain rule. -Dan
Another hint. y = y(x) so when you find [math]\dfrac{d}{dx} (y^3)[/math] you will need the chain rule. -Dan