Equation of a circle problem- give me a push

[synapsis]

I'm not sure where to go on this one, i think i just need a push in the right direction.

The problem is find an equation of the circle tangent to the y-axis, with center (3, -2)

What i know is the standard form for the equation of a circle.
(x - h)^2 + (y - k)^2 = r^2

I know the center (h, k) i just don't know how to solve for the radius.

I'm not sure how to get there, someone give me a push plz, i'm sure i can fight through it with a little help

-thx

 

[pka]

tangent to the y-axis, with center (3, -2)
That means the the radius is 3. Right? Why?

 

[synapsis]

its radius is 3 because the x coordinate is 3 and it is tangent to the y-axis? so the tangent point is (0 -2)?

 

[pka]

Good for you, you have got it!
Go for it!