evaluating exponents: [(3/4)^2 + (1/2)^3 + n]^0

Review your exponent rules. Hint: What is the value of anything to the zero power?

Eliz.
 
anything to a zero power is 1
[(.75)^2+ (.5)^3+3.14]
(.42)+(.12)+3.14
=3.68
 
zhyia said:
anything to a zero power is 1
Click to expand...
Correct.

zhyia said:
[(.75)^2+ (.5)^3+3.14]
Click to expand...
What happened to the "to the zero power" that used to be on the outer brackets?

zhyia said:
(.42)+(.12)+3.14
Click to expand...
No. The square of 3/4 is 9/16, not 42/100 = 21/50. The square of 1/2 is 1/4, not 12/100 = 3/25. Also, were you given that the value of the variable "n" was "3.14"? If so, then this should have been included in the original post. (It is difficult to provide relevant assistance if we have not been provided with the complete question.)

Thank you.

Eliz.
 
correction the problem was suppose to be [(¾)² + (½)³ + π]°

i came up with [9/16+1/8+3.14]1 which is 11/16+ 3.14 then i changed 11/16 to a decimal 0.69
=3.83 but im not sure what to do from this point?
 
zhyia said:
anything to a zero power is 1
Click to expand...
Whoops. What's this? 0<sup>0</sup>.

Better check to see that the base is NOT zero before jumping to conclusions.
 
zhyia said:
correction the problem was suppose to be [(¾)² + (½)³ + π]°

i came up with [9/16+1/8+3.14]1
Click to expand...
Why did you change the exponent from "0" to "1"?

Eliz.
 
I think poor zhyia did that from "anything to the power 0 = 1";
he/she thinks that means change the 0 to 1:
zhyia, that means THE ANSWER TO anything to the power 0 is 1;
no need to work out what's inside the brackets.

[anything]^0 = 1
-3^0 = 1
123456789^0 = 1
[speed of light times distance from Earth to Sun]^0 = 1 ; capish?????
 
...and I'm trying to point out that it requires at least a glance at the arguement, just to make sure it ISN'T zero.

0<sup>0</sup> generally would NOT be one (1).
 
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