Find expression for h?

[asfc2013]

A tank full of water is being drained through an outlet. The height H(m) of the water in the tank at any time t(s) is given by the differential equation:

. . . . .\(\displaystyle \dfrac{dH}{dt}\, =\, -0.0054\, \sqrt{H\,}\)

Given the initial condition H = 2 when t = 0, find an expression for H.

Unfortunately from online classes i missed this lesson and now have an assignment question that has to be solved however im struggling to work this one out! Any help and answer would be appreciated thankyou. Im very willing to learn how to solve this problem as its going to be part of my job. This forum is my last hope of learning and working this out. It would be very much appreciated. Im struggling to understand it.

Regards!

 

[Deleted member 4993]

A tank full of water is being drained through an outlet. The height H(m) of the water in the tank at any time t(s) is given by the differential equation:

. . . . .\(\displaystyle \dfrac{dH}{dt}\, =\, -0.0054\, \sqrt{H\,}\)

Given the initial condition H = 2 when t = 0, find an expression for H.

Unfortunately from online classes i missed this lesson and now have an assignment question that has to be solved however im struggling to work this one out! Any help and answer would be appreciated thankyou. Im very willing to learn how to solve this problem as its going to be part of my job. This forum is my last hope of learning and working this out. It would be very much appreciated. Im struggling to understand it.

Regards!

Can you express in words - what the differential equation is describing?

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[stapel]

A tank full of water is being drained through an outlet. The height H(m) of the water in the tank at any time t(s) is given by the differential equation:

. . . . .\(\displaystyle \dfrac{dH}{dt}\, =\, -0.0054\, \sqrt{H\,}\)

Given the initial condition H = 2 when t = 0, find an expression for H.

Unfortunately from online classes i missed this lesson....

What topic was covered that day? Which online lessons have you studied in an effort to replace that missing lecture?