Find the quotient and remainder when the first polynomial...

[lrinck]

Find the quotient and remainder when the first polynomial is divided by the second:

x^2-3x-54, x-9

How do you work this problem??

 

[Deleted member 4993]

Re: Find the quotient and remainder when the first polynomia

Find the quotient and remainder when the first polynomial is divided by the second?? x^2-3x-54, x-9 how do you work this problem??

My favorite two methods:

factorize then eliminate common factors

or

Synthetic division

What have you been taught?

 

[stapel]

How do you work this problem??

You do the long polynomial division (or synthetic division) -- unless your class covered some other method...?

. . . . .Google results for "long division polynomials"

. . . . .Google results for "synthetic division"

If you are supposed to be using some other method, please reply with clarification. Thank you!

Eliz.

 

[lrinck]

We do long division but im not gettin how to do it. I dont know why? Plz help

 

[Deleted member 4993]

Go to:

http://www.purplemath.com/modules/synthdiv.htm

for a quick review with example.

 

[lrinck]

ok thats dandy but how would you do b^6 + 8, b^2 +2

 

[stapel]

ok thats dandy but how would you do b^6 + 8, b^2 +2

If online lessons, on top of your book and the classroom lecture, have left you confused, then I'm afraid you need to consider getting face-to-face help. (Even were it reasonably feasible to attempt to teach lessons here, we'd just do something similar to the stuff you've already tried and didn't understand.)

Please see about hiring a qualified tutor, local to your area, and setting aside a few hours to get caught up on this material. Good luck!

Eliz.

 

[lrinck]

Im not an Idiot I would just like for you to help me with this one problem ok

 

[stapel]

I would just like for you to help me with this one problem

Show what you've done, and we'll be glad to help find any errors. :idea:

Please be complete. Thank you!

Eliz.

 

[Mrspi]

Here's a "dandy" suggestion....

Make sure that both divisor and dividend have ALL powers of the variable included.

You are dividing b^6 + 8 by b^2 + 2

So.....you are dividing b^6 + 0b^5 + 0b^4 + 0b^3 + 0b^2 + 0b + 8 BY b^2 + 0b + 2

Set it up as long division, and divide away!!

If you are still having trouble, please repost showing us exactly what you've done so we can see where your difficulties lie.