find vertex, axis, max, min, direction of y = -(x + 4)^2 - 2

qweenb212121

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Mar 14, 2007
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how do i do the following problem?

find vertex,axis,max,min,direction of parabola y = -(x + 4)^2 - 2
 
Hi.

there are some properties that you should understand.

first is your horizontal shift as defined by h(x) = f(x+c): which would move your parabola c units to the left of the origin. think + as left, and - as right

and then your reflection as defined by h(x) = -f(x): which is a reflection in the x-axis, from the negative on the outside.

-(x+4)^2 (reflection and shift left, 4 units)

you should be able to figure out what you need from there.

Your vertex is going to be (-4,0)

Questions to think about: Reflecting y=x^2 over the x-axis would make the parabola open up or down? The coordinates of your vertex tells you what about your axis of symmetry?

EDIT: you just changed your post and added a -2. ask one question at a time.
 
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