Finding minimum value of 3 + sqrt[2] cos(x + 20) on 0 <= x <= 360 degrees

[Beams]

Hi, I apologise if this is posted in the wrong section as I am new here.

I'm finding it difficult to solve this problem and I would really appreciate it if someone can help me and can explain what's going on step by step.

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2. Write down the minimum value of \(\displaystyle 3\, +\, \sqrt{\strut 2\,}\,\cos \left(x\, +\, 20\right)^{\circ}\) and find the value of x on the interval 0 < x < 360° for which it occurs.

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Thanks in advance.

 

[Deleted member 4993]

Hi, I apologise if this is posted in the wrong section as I am new here.

I'm finding it difficult to solve this problem and I would really appreciate it if someone can help me and can explain what's going on step by step.

---

2. Write down the minimum value of \(\displaystyle 3\, +\, \sqrt{\strut 2\,}\,\cos \left(x\, +\, 20\right)^{\circ}\) and find the value of x on the interval 0 < x < 360° for which it occurs.

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Thanks in advance.

At what value of Θ, we get the minimum value of cos(Θ)?