forgot an easy thing....

renegade05

Full Member
Joined
Sep 10, 2010
Messages
260
Alright, solving the following DE:

\(\displaystyle \frac{dy}{dx}= \frac{y}{x^2-x}\)

I got down to:

\(\displaystyle ln|y|=ln|x-1|-ln|x|+C\)

which can be written as:

\(\displaystyle |y|=C|\frac{x-1}{x}|\)

How can I solve for y explicitly ?

The full question is:

Find a DE for a function h with the property: tangent line to the curve at any point (x,) on the graph will pass through the point (x^2,2y). Solve the DE and express your final answer solved for y in simplified form. Find the curve that passes through (2,3).

I can solve the I.C., just need help with solving for y.
 
The point the curve has to pass through has both x and y positive. Further the graph cannot pass through x= 0 since y is not defined there.
 
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