Given m(CAD)=70° and m(BAC)=53°, find measure of arc FG

[Mathisconfusing101]

ok heres a new one...

Given mÐCAD=70° and mÐBAC=53°, find the measure of arc FG

35° 53° 70°

 

[mcrae]

ok heres a new one...

Given mÐCAD=70° and mÐBAC=53°, find the measure of arc FG

35° 53° 70°

angle CAD is = angle FAG, assuming that is what it means by 'arc FG'

 

[Mathisconfusing101]

awesome.. thanks!

 

[Mrspi]

ok heres a new one...

Given mÐCAD=70° and mÐBAC=53°, find the measure of arc FG

35° 53° 70°

Hi, Mathisconfusing101!

Unfortunately, you are being given some incorrect answers by some folks who mean well, but have a limited grasp of geometry. So, you're likely to end up more confused than you already are!

You have two concentric circles (circles with the same center). In such circles, arcs which have the same central angle have the same degree measure, and the degree measure of an arc is the same as the degree measure of its central angle.

Since central angle CAD has a measure of 70, then arc CD has a measure of 70, and SO DOES arc FG, because its central angle FAG is the same angle as CAD.

Not as difficult as you've been led to believe.