This is the equation h_a = 2(r)(r_a)/(r_a)-(r) where h_a is the height in relation to side a of a triangle, r is the radius of the incircle and r_a is the radius of the excircle.
I know all of them make 90º angles when they cut the triangle, and I also found out that A= (ar)(r_a)/(r_a)-r, where A is the triangle's area.
Thank you for your help.
I know all of them make 90º angles when they cut the triangle, and I also found out that A= (ar)(r_a)/(r_a)-r, where A is the triangle's area.
Thank you for your help.
