Find the value(s) of w so that the points (0,3) and (6,w) are 10 units apart.
OKay i think i have a really good idea on this problem, but something doesn't seem right, obviously because i'm not getting exactly the right answer according to my book. Here is my math, i need to know what i'm doing wrong. since i know the distance D = 10 and i solve for w
10 = sqrt of (6 - 0)^2 + (w - 3)^2
I square both sides to get rid of the sqrt
100= 36 +w^2 -6w +9
I subtract 36
64= w^2 - 6w +9
I subtract 64
0= w^2 -6w -55
this is factorable as w = 5 and w = -11 the book however has w= -5 and w= 11
is the book wrong or am i doing something wrong?
OKay i think i have a really good idea on this problem, but something doesn't seem right, obviously because i'm not getting exactly the right answer according to my book. Here is my math, i need to know what i'm doing wrong. since i know the distance D = 10 and i solve for w
10 = sqrt of (6 - 0)^2 + (w - 3)^2
I square both sides to get rid of the sqrt
100= 36 +w^2 -6w +9
I subtract 36
64= w^2 - 6w +9
I subtract 64
0= w^2 -6w -55
this is factorable as w = 5 and w = -11 the book however has w= -5 and w= 11
is the book wrong or am i doing something wrong?
