Help with simplifying a limit function.

[coooool222]

Hello I need help with this problem, they say that its -1. I looked it up and said I have to use derivatives but Im still on limits. We have not started derivatives yet so I have to simplify this algebraically. I am getting 0



(x-b)⁴⁹-x+b =
0

 

[Dr.Peterson]

Hello I need help with this problem, they say that its -1. I looked it up and said I have to use derivatives but Im still on limits. We have not started derivatives yet so I have to simplify this algebraically. I am getting 0

View attachment 34052

(x-b)⁴⁹-x+b =
0

What you're actually getting is not 0, but 0/0, which is indeterminate. That means you have to use a different method than just substituting.

See if you can factor (x-b) out of the numerator, in order to cancel it. Cancellation is a typical goal in limit problems.

 

[JeffM]

It would help if you showed a bit more of your working. I think you made a simple mistake in algebra.

It is I find frequently helpful to forget about the behaviour of the function at the limiting value initially. After all, the limit specifically does not include that value BY DEFINITION.

[math] x \ne b \text { and } y = \dfrac{(x - b)^{50} - x + b}{x - b} = \dfrac{(x - b)^{50} - (x - b)}{(x - b)} = \\ \dfrac{(x - b)\{(x - b)^{49} - 1\}}{(x - b)} \ne (x - b)^{49} - x + b. [/math]

 

[Dr.Peterson]

(x-b)⁴⁹-x+b =
0

I missed, before, the fact that you were not just evaluating the numerator, but making a faulty attempt to simplify.

You apparently just cancelled the (x-b) in the first term, but left the second term untouched, forgetting that both terms in the numerator are being divided by (x-b).

But my suggestion still stands: you need to factor the numerator, so that you can cancel a factor from the entire thing, not just one term. Alternatively, you can just divide each term by (x-b).

 

[Steven G]

Consider \(\displaystyle \dfrac{5+25}{5}=\dfrac{30}{5}=6\). Now let's try it your way. \(\displaystyle \dfrac{5+25}{5}\)=1+25 =26 (I reduced 5/5 to 2). Which is correct?

As Dr Peterson pointed out, you need to divide both factors in the numerator by 5, ie \(\displaystyle \dfrac{5+25}{5}=\dfrac{5}{5} +\dfrac{25}{5}\)=1 + 5 = 6