Help With Some Maths Please (projectile motion: distance traveled)

sjblencoe

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Jan 30, 2017
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I have tried to solve this problem myself but to no avail. Maths is not my strong point as you can probably tell. My problem is listed below, any help would be appreciated.

I launched my own rocket. The launch was just off vertical, at an angle of 89.8968°, on a bearing of 83°. The rocket reached 174.6km above sea level before crashing back to ground not too far away. I need to know the distance travelled please.


The following information was given.


* The rocket wasn't guided, nor propelled after take off. It followed the parabolic trajectory of a simple projectile.
* Both the launch point and landing site can be taken to be at sea level.
* Acceleration due to gravity is 9.81 m/s2.
* The effects of air resistance, the earth's rotation, etc., etc., etc. can be ignored.


imagepng
 
Okay, so you say you've tried to solve this problem, but weren't able to find the correct solution. That means you should have loads of work to show. As per the guidelines laid out in the Read Before Postinghttps://www.freemathhelp.com/forum/threads/41537-Read-Before-Posting!! thread that's stickied at the top of every sub-forum, please share with us any and all work you've done on the problem, even the parts you know for sure are wrong. Thank you.
 
When I say I have tried to solve the problem, I have looked at the equations I think I might need and still drawn a blank. Like I said, maths is a mystery to me and was hoping I would get a solution to the problem by asking on a forum such as this.

Apparently the below sets of numbers and letters are relevant. I have no idea at all and am looking for a solution.

- v = u + at
- s = ut + ½at^2
- s = vt - ½at^2
- s = ½(v + u)t
- v^2 = u^2 + 2as
 
I launched my own rocket. The launch was just off vertical, at an angle of 89.8968°, on a bearing of 83°. The rocket reached 174.6km above sea level before crashing back to ground not too far away. I need to know the distance travelled please.

The following information was given.

* The rocket wasn't guided, nor propelled after take off. It followed the parabolic trajectory of a simple projectile.
* Both the launch point and landing site can be taken to be at sea level.
* Acceleration due to gravity is 9.81 m/s2.
* The effects of air resistance, the earth's rotation, etc., etc., etc. can be ignored.

https://www.freemathhelp.com/forum/webkit-fake-url://7c296938-caff-4e29-812e-f8ad5d342b55/imagepng
When you say "distance", do you mean vertically (so you're trying to find the height) or along the flight-path (so you're needing a line integral)? The equations you reference in another post suggest the former, but I'd like to be sure.

Did your instructor not explain the equations you were given? If not (and assuming you meant "height"), then maybe this lesson might help.

By the way, if there was necessary information in your image, please repost, because it's not showing up. Thank you! ;)
 
That is for your reply. This is a personal challenge, nothing to do with a course. Just need babysitting throug it as I have limited math or physics skills. Hopefully you should see an image uploaded will explain the distance I need. It is the horizontal distance the rocket travels from point of launch to point of landing.
hope you can assist.
 

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That is for your reply. This is a personal challenge, nothing to do with a course. Just need babysitting throug it as I have limited math or physics skills. Hopefully you should see an image uploaded will explain the distance I need. It is the horizontal distance the rocket travels from point of launch to point of landing.
It looks like you're needing to learn about horizontal (and vertical) displacement. This will involve trigonometry as well as algebra and physics.

Since we cannot provide classroom instruction within this environment, you might want to take a glance at some online articles. There are some "calculators" in the listing at the link, too, if all you're needing is a numerical result. ;)
 
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