help!

Start with the equality:
4 - y/2 = 3 + y
Solve for y...what do you get?
 
I'm guessing you mean
(4-y)/2<3+y
4-y<6+2y
-2<3y
-2/3<y

BTW If you meant 4-(y/2) let me know and I'll try again. That's what you typed but use ()s to avoid confusion.
I'm not sure what you wanted with the "list" and "quote" BBCodes. It looks like you closed them without opening them.
 
Thanks Gene thats exactly what I meant...
I am a newbie to this site and am still not sure how to use symbols...
so luckily I am glad that someone understood what I was trying do...

:lol:
 
need help with another problem

l 2 - x/4 l - 3 greater than or equal to 1

the first part in absolute value...
 
Please post new questions as new threads, not as replies to old threads.

Please do not post the same question multiple times.

Thank you.

Eliz.
 
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