How to solve this differntial equation? dy/dt = (2-y)(5-y)
- Thread starter sonithcob
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Hint:
\(\displaystyle \dfrac{1}{(2-y)(5-y)} \ = \ \dfrac{1}{3} * \left [ \dfrac{1}{2-y} \ - \ \dfrac{1}{5-y} \right ] \)
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In case you're not sure what's going on in the first reply you received, think "partial fractions" (here).
oscarguevara
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dt= - (2-y) + (5-y) -2 /(2-y)(5-y)
t=ln(5-y)/(2-y)
2e^t - ye^t=5-y
2e^t -5= y(e^t - 1)
y=(2e^t -5)/y(e^t - 1) i allways forget the constant