There is a bamboo 20 ft high in which the upper end breaks and falls to the ground 6 ft from the stem. Set up and solve an equation that can be used to find the exact height of the break and exactly how much broke off.
I used a^2+b^2=c^2
I drew a right triangle and labeled the base (b) as 6 ft and side (a) as the height 20ft
c^2=6^2+20^2
c^2=36+400
The square root of c^2 = the square root of 436
C= 20.88
Than because the bamboo is 20 ft high I would subtract 20.88-20.00= .88 would be how much broke off?
I used a^2+b^2=c^2
I drew a right triangle and labeled the base (b) as 6 ft and side (a) as the height 20ft
c^2=6^2+20^2
c^2=36+400
The square root of c^2 = the square root of 436
C= 20.88
Than because the bamboo is 20 ft high I would subtract 20.88-20.00= .88 would be how much broke off?