if 0° ≤ θ < 360°.sin θ = 0.9625 with θ in QII, find θ to nearest tenth of degree

[LeDollface]

if 0° ≤ θ < 360°.sin θ = 0.9625 with θ in QII, find θ to nearest tenth of degree

Use the given information and a calculator to find θ to the nearest tenth of a degree if 0° ≤ θ < 360°.sin θ = 0.9625 with θ in QII

My answer has been incorrect twice, so after working on it a third time I thought I'd ask if I'm doing this correctly before submitting my answer again.

I found my answer as 105.74. If it is wrong can someone please explain why? Thank you!

 

[stapel]

Use the given information and a calculator to find θ to the nearest tenth of a degree if 0° ≤ θ < 360°.sin θ = 0.9625 with θ in QII

My answer has been incorrect twice, so after working on it a third time I thought I'd ask if I'm doing this correctly before submitting my answer again.

I found my answer as 105.74. If it is wrong can someone please explain why? Thank you!

Please reply showing your work and results, so that error-checking may be attempted. Thank you!

 

[Harry_the_cat]

Use the given information and a calculator to find θ to the nearest tenth of a degree if 0° ≤ θ < 360°.sin θ = 0.9625 with θ in QII

My answer has been incorrect twice, so after working on it a third time I thought I'd ask if I'm doing this correctly before submitting my answer again.

I found my answer as 105.74. If it is wrong can someone please explain why? Thank you!

Your post heading says "to the nearest tenth of a degree". That means one decimal place. You've given 2.