If X/a-b+c = Y/b-c+a = Z/c-a+b, Prove that : X+Y/a = Y+Z/b
- Thread starter jejo1
- Start date
- Joined
- Feb 4, 2004
- Messages
- 16,582
Sorry, but the policy you saw in the "Read Before Posting" announcement remains in effect; namely, we don't "do" students' work for them, nor do we provide complete solutions. Students still need to show some effort of their own.
What you have posted means the following:
. . . . .\(\displaystyle \mbox{If }\, \dfrac{X}{a}\, -\, b\, +\, c\, =\, \dfrac{Y}{b}\, -\, c\, +\, a\, =\, \dfrac{Z}{c}\, -\, a\, +\, b,\)
. . . . .\(\displaystyle \mbox{then prove that }\, X\, +\, \dfrac{Y}{a}\, =\, Y\, +\, \dfrac{Z}{b}\)
Was this what you meant?
When you reply, please include a clear listing of your thoughts and working so far. Thank you!
pka
Elite Member
- Joined
- Jan 29, 2005
- Messages
- 11,990
First the answer is absolutely not.
Second what you posted is an absolute unreadable mess.
Where are any grouping symbols? We cannot tell what numerator and/or denominator you mean.
It is also required that you show some work!
Oh, I didn't mean I need a complete work.. I wanted a complete proof to help me understand how this is made.Sorry, but the policy you saw in the "Read Before Posting" announcement remains in effect; namely, we don't "do" students' work for them, nor do we provide complete solutions. Students still need to show some effort of their own.
What you have posted means the following:
. . . . .\(\displaystyle \mbox{If }\, \dfrac{X}{a}\, -\, b\, +\, c\, =\, \dfrac{Y}{b}\, -\, c\, +\, a\, =\, \dfrac{Z}{c}\, -\, a\, +\, b,\)
. . . . .\(\displaystyle \mbox{then prove that }\, X\, +\, \dfrac{Y}{a}\, =\, Y\, +\, \dfrac{Z}{b}\)
Was this what you meant?
When you reply, please include a clear listing of your thoughts and working so far. Thank you!
Besides, I don't really know how you wrote the equation this way but that isn't what I meant.
I meant that the whole part after the (/) sign was the denominator. for example (X/a-b+c) X is the numerator and a-b+c is the denominator. after the equal sign the same applies. the part after prove that is alright.
- Joined
- Feb 4, 2004
- Messages
- 16,582
I'm sorry, but what is the difference between "a complete work" and "a complete proof" of the work, especially since "the work" is exactly "the proof"? :shock:
To learn how to type math as text (especially about how to use grouping symbols), try here. Your exercise, I think, is meant to be as follows:
. . . . .If X/(a-b+c) = Y/(b-c+a) = Z/(c-a+b), then prove that X + Y/a = Y + Z/b.
This typesets as:
. . . . .\(\displaystyle \mbox{If }\, \dfrac{X}{a\, -\, b\, +\, c}\, =\, \dfrac{Y}{b\, -\, c\, +\, a}\, =\, \dfrac{Z}{c\, -\, a\, +\, b},\)
. . . . .\(\displaystyle \mbox{then prove that }\, X\, +\, \dfrac{Y}{a}\, =\, Y\, +\, \dfrac{Z}{b}\)
Please reply showing your thoughts and efforts so far. For instance, you started by picking a pair of equal "fractions" from the original equation (say, the first two), cross-multiplied, and... then what? Please be complete. Thank you!