Individual Periodic Functions Project

inception

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Jan 23, 2011
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I have the following homework assignment (senior in high school): there are two periodic functions to investigate of the form y=f(x)=a*sin(bx) c*cos(dx). You will find and organize values of each function into a table and plot the points in a graph. I have values for x, but need to organize values into a table then plot points in a graph and am lost at this point with how to proceed.
 
Have you tried substitution? It helps if you stick to standard, or well-known values.
 
I have values for a, b,c, and d (1,2,3,3), giving me 1*sin(2x)+3*cos(3x). I have also calculated the values for x in the following table. My problem is solving for F(x) so that I can graph it. I'm unsure what to do at this point. Any help or suggestions would be appreciated.
x
-12.57
-11.00
-9.42
-7.85
-6.28
-5.50
-4.71
-3.93
-3.14
-2.62
-2.36
-2.09
-1.57
-1.05
-0.79
-0.52
0.00
0.52
0.79
1.05
1.57
2.09
2.36
2.62
3.14
3.93
4.71
5.50
6.28
7.85
9.42
11.00
12.57
 
inception said:
My problem is solving for F(x) so that I can graph it.

I think that you mean "evaluating f(x)" instead of "solving for F(x)" because there is nothing to solve, when forming a table of (x,y) values to plot.

Your original post talks about two periodic functions; it now seems that there is only one function, and that you forgot to type the plus sign, in your original post.

Also, the names f and F are not the same, so please pick one and stick to it.

f(x) = sin(2x) + 3 cos(3x)

Your first x-value listed is -4 Pi (rounded to two places).

To "evaluate" f(x) when x = -4 Pi means to find the number which is represented by the symbol f(-4 Pi).

Finding this value is as simple as substituting the number -4 Pi for the variable x in your function definition, followed by using a scientific calculator to do the arithmetic with the sine and cosine values. If you're using a graphing calculator, you should be able to enter the following exactly as shown.

sin(2*(-12.57))+3*cos(3*(-12.57))

The result displayed should look something like 2.999999989 or 3.000000011.

This means that the value of f(x) is 3 when x is -4 Pi. In other words, the point (-12.57, 3) is on the graph of function f.

Most graphing calculators will generate such a table of (x,y) values for you automatically. You can specify the restricted domain from -4 Pi through 4 Pi. You can even specify the distance between x-values in the table (every Pi/2, for example).

Actually, the machine will draw the graph, too!

Is this exercise strictly an exercise in graphing?

 
The first part is to graph...then I have to describe such properties as domain, range, zeros, period, and amplitude. Thank you sooo much for your help!!
 
You will also want to make sure you are in RADIAN mode and not DEGREE mode.
 
You must have been reading my mind 'cause I kept getting 1.94 in Degree mode and was about to email you again. Once again...thanks! This was driving me crazy.
 
inception said:
You must have been reading my mind 'cause I kept getting 1.94 in Degree mode and was about to email you again. Once again...thanks! This was driving me crazy.
Well, look on positive side: it'll never happen again, right ? :idea:
 
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