Joint Probability

[smokey10]

I need help solving the following problem. I know the formula is p(a)+p(b)-p(a&b). Please help me to understand where to plug in the numbers correctly and solve.

A student is taking two courses, history and math. The probability the student will pass the history course is 0.60, and the probability of passing the math course is 0.39. The probability of passing both is 0.32. Thanks.

 

[stapel]

I need help solving the following problem. I know the formula is p(a)+p(b)-p(a&b). Please help me to understand where to plug in the numbers correctly and solve.

A student is taking two courses, history and math. The probability the student will pass the history course is 0.60, and the probability of passing the math course is 0.39. The probability of passing both is 0.32.

The exercise appears to contain only statements. There is no question. What are you supposed to be "solving"? Thank you!

 

[pka]

I need help solving the following problem.
I know the formula is p(a)+p(b)-p(a&b).
Please help me to understand where to plug in the numbers correctly and solve.

A student is taking two courses, history and math. The probability the student will pass the history course is 0.60, and the probability of passing the math course is 0.39. The probability of passing both is 0.32.

@smokey1: There are many things wrong with this post, what you posted is only a partial expression.

I think you mean: \(\displaystyle \mathcal{P}(A\cup B)=\mathcal{P}(A)+\mathcal{P}(B)-\mathcal{P}(A\cap B)~?\) That is the probability that at least one of \(\displaystyle A\text{ or }B\) occurs.

So \(\displaystyle 0.6+0.39-0.32=\) the probability that at least one course is passed.