I need to build a lattice that is going to fit into a frame that will be 575 mm x 1426mm inside dimensions. It will have a frame around it that is 19.275 mm thick all around. The thickness (width) of the lattice material will also be 19.275mm. The lattes will be diagonal in the frame.
What I need to establish is what the distance would be between the centers of dados cut as half laps in the lattice to create a symmetrical pattern in the frame. And so that around the edge the openings would exactly half of a square.
Thanks
Dave
Just some rambling - check it before you you use it.
Assume the upper left corner has a latte cut to a point which fits into the corner and each center of the latte cut at 45 degrees is x mm going to the right [the latte running parallel to the one going into the corner]. Coming from the other direction with those lattes going down to the left, we have the same thing so the total distance is equal to
n x = 1426
where x is the distance between latte centers and n is the number of lattes going down to the right. I'm assuming the lattes are cut at a 45 degree angle and overlapped to be nailed to the frame.
Going up and down, i.e. start at the lower right corner and go up or upper left corner and go down, we the same thing (but a different number of lattes), i.e.
m x = 575
So
n = (1426 / x) = 1426 / (575 / m) = (1426 / 575) m = 2.48 m
It looks like the inside (outside) square should be about 3 (5) times the width of your lattes so the square, center of latte to center of latte, should be about 4 widths. The x is the diagonal of that square so x ~ 1.414 * 4 * 19.275 ~ 109.0; or m ~ 757 / 109 ~ 5.2 and n ~ 13. Or play around with other measurements.
Oh, I would play around with this some to see how it comes out. You note that if n is an even number, m isn't (and vice versa). until, that is, the squares get very small and start to overlap.
EDIT: Note that 2n is about the number of lattes going each way and n/m is just the number of lattes nailed to the top (and bottom) side/left (and right) side.