Karrie1113
New member
- Joined
- Aug 26, 2010
- Messages
- 7
bicyclist and jogger leave the gym at the same time. Bicyclist rides 6mph faster than the jogger. it takes the jogger 2 hr to complete the same distance as the bicyclist in 1 hour. find the speed of each person.
Here are my thoughts
rate*Time=Distance
RIDER
Rate=R+6
time =1 hr
distance is 1(R+6)
JOGGER
rate=R
time =2 hr
distance = 2(R)
Equation 1(R+6)=2(r)
1R+6=2R
subtract 6 from both sides
1R=2R-6
subtract 2R from both sides
-R=-6
R=6
Is this correct?
Here are my thoughts
rate*Time=Distance
RIDER
Rate=R+6
time =1 hr
distance is 1(R+6)
JOGGER
rate=R
time =2 hr
distance = 2(R)
Equation 1(R+6)=2(r)
1R+6=2R
subtract 6 from both sides
1R=2R-6
subtract 2R from both sides
-R=-6
R=6
Is this correct?