Medians

[broadwaygrl419]

Write an equation for the median from A to BC if the coordinates are: A(6,6), B(2,-5) & C(-6,4)

~I know that the coordinates form triangle ABC. I also know that the midpoint of BC is (-2,-.05). I am stuck on how I should write an equation for the median formed by A (6,6) and the midpoint of BC (-2,-.05)

 

[tkhunny]

You could try the two-point form of a line.

 

[Aladdin]

You have two points on a line and this is sufficient to find its slope :

Let N(-2,-0.5) be the mipoint of BC .

Slope of AN (median) = \(\displaystyle \frac{yN - yA}{xN - xA}\)

 

[Deleted member 4993]

Write an equation for the median from A to BC if the coordinates are: A(6,6), B(2,-5) & C(-6,4)

~I know that the coordinates form triangle ABC. I also know that the midpoint of BC is (-2,-.05). I am stuck on how I should write an equation for the median formed by A (6,6) and the midpoint of BC (-2,-.05)

Slope of a line passing through (x[sub:148cu6ug]1[/sub:148cu6ug],y[sub:148cu6ug]1[/sub:148cu6ug]) and (x[sub:148cu6ug]2[/sub:148cu6ug],y[sub:148cu6ug]2[/sub:148cu6ug]) = [y[sub:148cu6ug]2[/sub:148cu6ug] - y[sub:148cu6ug]1[/sub:148cu6ug]] /[x[sub:148cu6ug]2[/sub:148cu6ug] - x[sub:148cu6ug]1[/sub:148cu6ug]]

.

 

[broadwaygrl419]

That makes sense, we are re-covering those ideas from algebra. Thanks so much!