[MOVED] help with simplifying product of ratnl expressions

[susan pearson]

i think that i've finally figured this out, can someone check my answer?
I am supposed to perform the indicated operation.

6w^2 + 5w - 6 9w^2 - 4
------------------------- . ------------------------- =
4w^2 - 9 6w^2 - 5w -6



the answer i came up with is 3(18w^2 + 15w - 26) - 4
----------------------------
2(12w^2 - 10w - 39) + 9

 

[tkhunny]

You can use this guy "^" for exponents. Shift-6

x-squared would be x^2

Space it from it's neighbors: x^2 + 1

Add parentheses for clarity and to say what you mean: (x^2 + 1)/(y^3 - 12)

How can one check your answer if you don't tell us what it is?

 

[susan pearson]

thanks, i've added my answer

You can use this guy "^" for exponents. Shift-6

x-squared would be x^2

Space it from it's neighbors: x^2 + 1

Add parentheses for clarity and to say what you mean: (x^2 + 1)/(y^3 - 12)

How can one check your answer if you don't tell us what it is?

 

[skeeter]

Re: [MOVED] help with simplifying product of ratnl expressio

i think that i've finally figured this out, can someone check my answer?
I am supposed to perform the indicated operation.

6w^2 + 5w - 6 9w^2 - 4
------------------------- . ------------------------- =
4w^2 - 9 6w^2 - 5w -6



the answer i came up with is 3(18w^2 + 15w - 26) - 4
----------------------------
2(12w^2 - 10w - 39) + 9

I have absolutely no no idea what you did to get that "answer".



start by factoring each numerator and denominator ...

(6w^2 + 5w - 6)/(4w^2 - 9) * (9w^2 - 4)/(6w^2 - 5w - 6) =

(3w - 2)(2w + 3)/[(2w - 3)(2w + 3)] * (3w - 2)(3w + 2)/[(3w + 2)(2w - 3)] =

multiply the fractions straight across ...

(3w - 2)(2w + 3)(3w - 2)(3w + 2)/[(2w - 3)(2w + 3)(3w + 2)(2w - 3)] =

cancel the common factors in the numerator and denominator ...

(3w - 2)(3w - 2)/[(2w - 3)(2w - 3)] =

simplify the result ...

(3w - 2)²/(2w - 3)²