Solar_blaze
New member
- Joined
- Apr 20, 2015
- Messages
- 42
I got a question I am confused with
In triangle ABC Side of the triangle BC is sitting on the line of
Y=5X-13 The edge A is (1,6)
The side of triangle AC is parallel to the line 3y-X-4=0.
The side of triangle AB is parallel to the line y=-2X+10.
Find the Coordinates of the edges B and C.
Excuse if my English writing is not mathematically right it's not my native language.
So far I did this
In order to find B I took
-2X+10=5X-13
Found X=3
But I don't know where to put X=3 now in which equation and why?
In triangle ABC Side of the triangle BC is sitting on the line of
Y=5X-13 The edge A is (1,6)
The side of triangle AC is parallel to the line 3y-X-4=0.
The side of triangle AB is parallel to the line y=-2X+10.
Find the Coordinates of the edges B and C.
Excuse if my English writing is not mathematically right it's not my native language.
So far I did this
In order to find B I took
-2X+10=5X-13
Found X=3
But I don't know where to put X=3 now in which equation and why?