Hello Brothers,
I'm a brazilian admirator of math and philosofy, my english is very poor, because I ask apologize antecipated.
I whish yours opinion about a theorem, if I must go on, or forget about. let see:
Became G a set of total possible of existence, in the form:
{x e G/ x property of a total possible of existence}
think existence in all levels.
Theorem: First cause
"If set G is not a subset of nine other existent set, what import to say, him is self cause, so him is perfect, and finite."
Prove for contradiction: G is not a subset, but is imperfect. So must exist least one element what is not a property of G,
became possible a existence of a set compound by elements of G and a least one element, so G became a subset. Absurd(contradiction).
in other hand, let see: the set G is perfect, but is a subset of another set. but if G is all possible of existence, a set what a contain G do no property
elements , because this not have existence of ents what sustain this set. Absurd(contradiction).
Q.E.D.
if theorem is true, let say what set exist, is cause by yourself and perfect e finite. I know what this prove seems very simple, but if is true another consequences of him, maybe not be so simple.
thanks antecipated,
Atenciously,
Lucio Marcos Lemgruber
Dear friends,
A first problem whith a theorem,is that, the definition of set leaves a russell paradox, so, I have try solve the problem saying what exist a other contradiction before a paradox, is that, how can be a set of the all other sets if all other sets be in using, must be another thing not a set, \I confess,
not know call that, either proof a existence of entity, but is the way open!
Lucio
I'm a brazilian admirator of math and philosofy, my english is very poor, because I ask apologize antecipated.
I whish yours opinion about a theorem, if I must go on, or forget about. let see:
Became G a set of total possible of existence, in the form:
{x e G/ x property of a total possible of existence}
think existence in all levels.
Theorem: First cause
"If set G is not a subset of nine other existent set, what import to say, him is self cause, so him is perfect, and finite."
Prove for contradiction: G is not a subset, but is imperfect. So must exist least one element what is not a property of G,
became possible a existence of a set compound by elements of G and a least one element, so G became a subset. Absurd(contradiction).
in other hand, let see: the set G is perfect, but is a subset of another set. but if G is all possible of existence, a set what a contain G do no property
elements , because this not have existence of ents what sustain this set. Absurd(contradiction).
Q.E.D.
if theorem is true, let say what set exist, is cause by yourself and perfect e finite. I know what this prove seems very simple, but if is true another consequences of him, maybe not be so simple.
thanks antecipated,
Atenciously,
Lucio Marcos Lemgruber
Dear friends,
A first problem whith a theorem,is that, the definition of set leaves a russell paradox, so, I have try solve the problem saying what exist a other contradiction before a paradox, is that, how can be a set of the all other sets if all other sets be in using, must be another thing not a set, \I confess,
not know call that, either proof a existence of entity, but is the way open!
Lucio
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