Extend segment BX to meet segment AC at a point we'll call D.
Now, we have a new triangle ADX, for which angle BXA is an exterior angle. The measure of an exterior angle of a triangle is greater than the measure of either remote interior angle of the triangle. <ADX is an exterior angle, and so m<BXA > m<ADX.
Next, notice that <ADX is an exterior angle for triangle DCB. And so m<ADX is greater than the measure of either remote interior angle for triangle DCB. ONE of the remote interior angles is <C. Therefore, m<ADX > m<C.
Ok....if m<BXA > m<ADX, and m<ADX > m<C, what can you conclude, and why?
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