Ordinary annuity

[Blake corey]

Every quarter, a couple deposits P2,000 in an account that pays compounded quarterly. If the first deposit was made on Oct. 1, 2001, how much will be in their account just after their 10th deposit?

I know the formula is Sd=R(1+i) n+1-1-1÷i
And the answer but my quesion is how to solve this after the 10th deposit?

 

[Steven G]

R(n+i)n+1-1-1/i = R(n+i)n - 1/i since 1-1 = 0. Is that what Sd should equal?

Can we see your work so we know what type of help you need.

 

[Blake corey]

R(n+i)n+1-1-1/i = R(n+i)n - 1/i since 1-1 = 0. Is that what Sd should equal?

Can we see your work so we know what type of help you need.

I have able solve it now
But thanks.