Partial fractions with a constant factor in the denominator, why is it ignored?

[wduk]

Hello

Say i have:

(x-3) / (2(x-1)(x+2)(2x-1))

This becomes:

A/(x-1) + B/(x+2) + C/(2x-1)

But the 2 in the denominator seems to not be included, why is it ignored, i don't understand the logic behind that.

 

[Deleted member 4993]

Hello

Say i have:

(x-3) / (2(x-1)(x+2)(2x-1))

This becomes:

A/(x-1) + B/(x+2) + C/(2x-1)

But the 2 in the denominator seems to not be included, why is it ignored, i don't understand the logic behind that.

For what type of problems - are you using partial fractions? If you included the constant term in the denominator - what type of numerator would you assign for that?

 

[tkhunny]

Why do you think it is ignored? \(\displaystyle \dfrac{1}{2\cdot(x+2)} = \dfrac{1/2}{x+2}\). It isn't an equivalent expression if you ignore it.