please check my work: Let f(x) = |x - 1| + x - 1

[Guest]

Let f(x) = |x - 1| + x - 1

(a) Sketch the graph of f(x)
(b) Find lim x-> -2 f(x)
(c) Find lim x->2 f(x)

solution:

. . .f(x) = |x - 1| + x - 1

. . .(b) |-2 - 2| - 2 - 2 = 4 - 4 = 0
. . .(c) |2 - 1| + 2 - 1 = 1 + 2 - 1 = 2

 

[tkhunny]

(b) and (c) - You had better KNOW it's continuous and defined before you start plugging things in.

Well, graph it.

For x > 1, |x-1| = x-1 and we have f(x) = 2x-2
For x < 1, |x-1| = 1-x and we have f(x) = 0