I imagine that whoever gave you this problem expects you to know the "half angle formula"Hi im new to this forum
can anyone help me to find the exact value of this question. I know its easy but..
If cosA= 3/4 ,Find the exact value of cos1/2A. ?![]()
Hi im new to this forum
can anyone help me to find the exact value of this question. I know its easy but..
If cosA= 3/4 ,Find the exact value of cos1/2A. ?![]()
I imagine that whoever gave you this problem expects you to know the "half angle formula"
\(\displaystyle cos(\frac{A}{2})= \pm\sqrt{\frac{1}{2}(1+ cos(A)}\). Of course to give the exact value, you would have to have more information. For example, if cos(A)= 1/2, then cos(A/2) may be \(\displaystyle \frac{\sqrt{3}}{2}\) (\(\displaystyle A= \frac{\pi}{3}\) radians) or \(\displaystyle -\frac{\sqrt{3}}{2}\) (\(\displaystyle A= \frac{5\pi}{3}\) radians).
Like HOI mentioned, high likelihood you are supposed to know the half angle formulas. That being said:
\(\displaystyle cos(\dfrac{A}{2})= \pm\sqrt{\dfrac{1}{2}(1+ cos(A)}\)
\(\displaystyle = \pm\sqrt{\dfrac{1}{2}(1+ \dfrac{3}{4})}\)
Can you take it from here?