Possible answers for (a + jb)^1/2

markbrock30

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Mar 5, 2008
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Hi,

Given the equation (a + jb)^1/2, and being asked to solve it, will the angle of the second answer be 180 degrees out of phase, or 360 degrees out of phase?

i.e Will the second answer be in the same place, but with a full rotation, or on the opposite side?


Cheers,

Mark.
 
markbrock30 said:
Given the equation (a + jb)^1/2, and being asked to solve it, will the angle of the second answer be 180 degrees out of phase, or 360 degrees out of phase?
I'm sorry, but (a + jb)[sup:2x5s1je6]1/2[/sup:2x5s1je6] is an expression, not an equation, so there is nothing to "solve". From the mention of angles and phases, it would appear that this probably relates to trigonometry in some manner...?

Please reply with the full and exact text of the exercise, the complete instructions, a scan or detailed description of any necessary graphic, and a clear listing of your work and reasoning so far. Thank you.

Eliz.
 
Hi Eliz,

Thanks, but I figured it out.

You were right, I was thinking about the problem in the wrong way.

Let Theta = x, and A>0 = the polar form representation of a + jb.

(a + jb)^1/2
=(A>0)^1/2
=( Ae^(j.x) )^1/2
= A^1/2.e^(j.1/2.x)

Let A^1/2 = B.

= B.e^(j.1/2.x)
= B>(1/2.x)
= B>(1/2.x + 2.n.PI) -> When n is the number of circular rotations.


Cheers,

Mark.
 
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