Prove the following:
cot^2A + csc^2A = -cot^4A + csc^4A
Here is what I have so far…
First I saw that I can factor out a -1 and I have a difference of two squares.
= -1(cot^4A – csc^4A)
= (cot^2A – csc^2A)(cot^2A + csc^2A)
= (cot A – csc A)(cot A + csc A)(cot^2A + csc^2A)
= (cosA-1/sinA)(cosA+1/sinA)(cot^2A + csc^2A)
= ((cosA – 1)(cosA+1)/sinA)(cot^2A + csc^2A)
=sin^2A/sinA(cot^2A + csc^2A)
= sinA(cot^2A + csc^2A)
That’s as far as I got…and it isn’t proven this way…any help would be appreciated.
cot^2A + csc^2A = -cot^4A + csc^4A
Here is what I have so far…
First I saw that I can factor out a -1 and I have a difference of two squares.
= -1(cot^4A – csc^4A)
= (cot^2A – csc^2A)(cot^2A + csc^2A)
= (cot A – csc A)(cot A + csc A)(cot^2A + csc^2A)
= (cosA-1/sinA)(cosA+1/sinA)(cot^2A + csc^2A)
= ((cosA – 1)(cosA+1)/sinA)(cot^2A + csc^2A)
=sin^2A/sinA(cot^2A + csc^2A)
= sinA(cot^2A + csc^2A)
That’s as far as I got…and it isn’t proven this way…any help would be appreciated.