quadratic problem

[Shoppingal]

the population of a town is modelled by the function P(t) = 6t^2 + 110t + 4000, where P(t) is the population and t is the time in years since 2000. When will the population be 6000?

P(t) = 6t^2 + 110t + 4000
6000 = 6t^2 + 110t + 4000
6000 - 4000 = 6t^2 + 110t
2000 = 6t^2 + 110t

totally lost any help would be appriecated.

 

[Shoppingal]

So 6t² + 110t - 2000 = 0. Apply the quadratic formula.

I applied the quadratic formula but I am still getting the wrong answer
I get 135.12 or -29.59 it should be 2011
I would show my work but I don't know how to make the square root icon here.

 

[Jt00]

if you are unsure of how to make the square root icon (i am too), a good substitute is the abbreviation "sqrt", with the part of the equation that is under the square root (or x root) in parentheses.

 

[Mrspi]

I applied the quadratic formula but I am still getting the wrong answer
I get 135.12 or -29.59 it should be 2011
I would show my work but I don't know how to make the square root icon here.

In order for us to see WHY you are getting an incorrect answer using the quadratic formula on an equation which is correct, we need to see your work.

a = 6
b = -110
c = -2000

I'm guessing you have an error in entering the calculation in your calculator, or in applying the correct order of operations. It worked for me...rounded to the nearest whole number of years, t = 11, and since t is the number of years AFTER 2000, you need to add 11 to 2000, producing the year 2011.