Hello,
The question is solve the triangle where a = 22.24 cm, b = 9.74 cm, A = 33.3 degrees.
I understand that it is an SSA triangle so I use a/sinA = b/sinB. I plug that in being 22.24/sin33.3 = 9.74/sinB. I then solve for sinB.
-----> sinB = 9.74sin33.3/22.24 - I then get sinB = .2404. Now here is my problem. It says there are two angles that are less than 180 degrees that have the sine = .2404.
How do I find these two angles? The answer states that the two angles are 13.9 degrees and 166.1 degrees. How would one go about finding them?
I understand the rest of the problem, besides that part (finding the two angles).
Thanks for the help
The question is solve the triangle where a = 22.24 cm, b = 9.74 cm, A = 33.3 degrees.
I understand that it is an SSA triangle so I use a/sinA = b/sinB. I plug that in being 22.24/sin33.3 = 9.74/sinB. I then solve for sinB.
-----> sinB = 9.74sin33.3/22.24 - I then get sinB = .2404. Now here is my problem. It says there are two angles that are less than 180 degrees that have the sine = .2404.
How do I find these two angles? The answer states that the two angles are 13.9 degrees and 166.1 degrees. How would one go about finding them?
I understand the rest of the problem, besides that part (finding the two angles).
Thanks for the help