These kinds of problems are killing me on homework. Causing me to be stuck for at least an hour on one problem:
\(\displaystyle \sin\dfrac{\pi}{3}(\cos\dfrac{\pi}{3}) - \tan\dfrac{\pi}{4}\)
\(\displaystyle \dfrac{\sqrt{3}}{2}(\dfrac{1}{2}) - 1\)
\(\displaystyle \dfrac{\sqrt{3}}{4} - 1\)
\(\displaystyle \dfrac{\sqrt{3}}{4} - \dfrac{4}{4}\)
Probably this answer will be wrong.
Well actually I checked now and it was right.
The problem is the homework wants it reduced down to a certain level. For instance, it might want \(\displaystyle \dfrac{\sqrt{3}}{4} - \dfrac{4}{4}\) written as \(\displaystyle \dfrac{\sqrt{3} - 4}{4}\)or visa versa, and if it's not the way they want it, then it's wrong.
\(\displaystyle \sin\dfrac{\pi}{3}(\cos\dfrac{\pi}{3}) - \tan\dfrac{\pi}{4}\)
\(\displaystyle \dfrac{\sqrt{3}}{2}(\dfrac{1}{2}) - 1\)
\(\displaystyle \dfrac{\sqrt{3}}{4} - 1\)
\(\displaystyle \dfrac{\sqrt{3}}{4} - \dfrac{4}{4}\)
Probably this answer will be wrong.
The problem is the homework wants it reduced down to a certain level. For instance, it might want \(\displaystyle \dfrac{\sqrt{3}}{4} - \dfrac{4}{4}\) written as \(\displaystyle \dfrac{\sqrt{3} - 4}{4}\)or visa versa, and if it's not the way they want it, then it's wrong.
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