I don't understand why: (cosx)^2 (sinx)^2 = (1/4)(sin2x)^2 what identities are used here? Thanks!
M monokill New member Joined Mar 2, 2008 Messages 6 May 10, 2008 #1 I don't understand why: (cosx)^2 (sinx)^2 = (1/4)(sin2x)^2 what identities are used here? Thanks!
L Loren Senior Member Joined Aug 28, 2007 Messages 1,299 May 11, 2008 #2 Re: simple identity trick sin 2x = 2sin x cos x Start on the right side. And it's not a TRICK.