I need help to solve the following equation: Sin(317x) = Sin (317x-10/3) Thank you in advance!
R rah87 New member Joined Feb 4, 2011 Messages 1 Feb 4, 2011 #1 I need help to solve the following equation: Sin(317x) = Sin (317x-10/3) Thank you in advance!
D Denis Senior Member Joined Feb 17, 2004 Messages 1,707 Feb 4, 2011 #2 rah87 said: Sin(317x) = Sin (317x-10/3) Click to expand... Same as having: 2x = 2x + 5 :shock:
S soroban Elite Member Joined Jan 28, 2005 Messages 5,586 Feb 4, 2011 #3 Hello, rah87! \(\displaystyle \text{Solve for }x\!:\;\;\sin(317x) \:=\: \sin (317x-\tfrac{10}{3})\) Click to expand... The equation is satisfied if the two angles are supplementary. . . \(\displaystyle 317x + (317x - \tfrac{10}{3}) \:=\:\pi \quad\Rightarrow\quad 634x \:=\:\pi + \tfrac{10}{3} \:=\:\tfrac{3\pi+10}{3}\) \(\displaystyle \text{Therefore: }\;x \;=\;\frac{3\pi+10}{1902}\)
Hello, rah87! \(\displaystyle \text{Solve for }x\!:\;\;\sin(317x) \:=\: \sin (317x-\tfrac{10}{3})\) Click to expand... The equation is satisfied if the two angles are supplementary. . . \(\displaystyle 317x + (317x - \tfrac{10}{3}) \:=\:\pi \quad\Rightarrow\quad 634x \:=\:\pi + \tfrac{10}{3} \:=\:\tfrac{3\pi+10}{3}\) \(\displaystyle \text{Therefore: }\;x \;=\;\frac{3\pi+10}{1902}\)
