Solving Geom. Word Probs: w is 6 less than L; L is twice w

[Gabriela]

The width of a rectangle is 6 centimeters less than the length. The perimeter is 64 centimeters. Find the Width.
w = / - 6

P = 2(/) + 2(/) - 6
64 = 2(/) + 2(/) - 12 = 64 + 12 = 76
76 = 4/ = 76 ÷ 4 = 19
/ = 19 - 6
/ = 13
The width of the rectangle is 13 centimeters. (Is this Correct?)
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The length of a rectangle is twice the width; the perimeter is 42 inches. Find the width.
/ = w x 2

P = 2(w) + 2(w) x 2
42 = 2(w) + 2(w) x 2 (What do I do next?)

 

[skeeter]

Re: Solving Geometry Word Problems

The width of a rectangle is 6 centimeters less than the length. The perimeter is 64 centimeters. Find the Width.
w = / - 6

P = 2(/) + 2(/) - 6
should be P = 2L + 2(L - 6) ... now give it a go

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The length of a rectangle is twice the width; the perimeter is 42 inches. Find the width.
/ = w x 2

P = 2(w) + 2(w) x 2
[
42 = 2(w) + 2(w) x 2
(What do I do next?)

42 = 2W + 4W
42 = 6W
finish

 

[Gabriela]

Solving Geometry Word Problems (New Question)

What is the formula to resolve the following exercise based on the "Area" instead of the perimeter? P = 2(w) + 2(w x 3)

The length of a rectangle is three times the width. What is the width if the area is 147 square feet?
L = w x 3

A = 2(w) + 2(w x 3)
147 = 2(w) + 2(w x 3)
147 = 2w + 6w
147 = 8w ??????

 

[Deleted member 4993]

Re: Solving Geometry Word Problems (New Question)

What is the formula to resolve the following exercise based on the "Area" instead of the perimeter? P = 2(w) + 2(w x 3)

The length of a rectangle is three times the width. What is the width if the area is 147 square feet?
L = w x 3

A = 2(w) + 2(w x 3)<<< That is formula for perimeter - not Area

A = w * (w * 3) ___ Start using '*' for multiplication to avoid confusion with 'x' as a variable name

Now continue...

147 = 2(w) + 2(w x 3)
147 = 2w + 6w
147 = 8w ??????

 

[Gabriela]

Solving Geometry Word Problems

The length of a rectangle is three times the wide. What is the width if the area is 147 square feet?
A = w * (w * 3)

147 = 2w * 2(w * 3)
147 = 2w * 6w
147 = 12w ?????

Thank you for giving me the formula to finish this excercise. I am still having trouble finishing it. I don't know what comes next. A division?, a multiplication?

 

[skeeter]

Re: Solving Geometry Word Problems

The length of a rectangle is three times the wide. What is the width if the area is 147 square feet?
A = w * (w * 3)

w*(w * 3) = 3w[sup:no4jbc4x]2[/sup:no4jbc4x]
so 147 = 3w[sup:no4jbc4x]2[/sup:no4jbc4x]
solve for w

 

[Denis]

Re: Solving Geometry Word Problems

The length of a rectangle is three times the wide. What is the width if the area is 147 square feet?
A = w * (w * 3)

147 = 2w * 2(w * 3)
147 = 2w * 6w
147 = 12w ?????

Thank you for giving me the formula to finish this excercise. I am still having trouble finishing it. I don't know what comes next. A division?, a multiplication?

WHY did you change the formula: why did you add in the two 2's?
Do you understand that w * w = w^2 ; do you know what w^2 stands for? If not, only your teacher can help you...

 

[Gabriela]

Solving Geometry Word Problems

THANK YOU ALL FOR YOUR HELP.