solving trigonometry with algegra

Muisies said:
solve cos(x -2pi/3) = 1/2 -2pi<x<2pi

Please explain the steps.
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Look at the unit circle and decide for which value of Θ you would have cos(Θ) = 1/2 within the domain of (-2π - 2π/3) < Θ < (2π - 2π/3)
 
Muisies said:
Please explain the steps.
Click to expand...
They were supposed to have explained the steps in your textbook and in your class. Have they not? :shock:

Muisies said:
solve cos(x -2pi/3) = 1/2, -2pi<x<2pi
Click to expand...
What basic reference angles have they given you? Which angle relates to a cosine value of one-half? Given this angle value and that it equals x - (2pi)/3, what must be the (basic reference angle) value of x?

What do you know about how cosine moves? How do its values repeat over its period? Then how will the given cosine expression repeat? How will x repeat?

Please be complete. Thank you! ;)
 
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