logistic_guy
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What is the momentum of a proton traveling at \(\displaystyle v = 0.85c\)?
Special Theory of Relativity
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logistic_guy
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I have never seen beauty like this.
\(\displaystyle p = \frac{mv}{\sqrt{1-\frac{v^2}{c^2}}} = \frac{1.67 \times 10^{-27}(0.85)(299792458)}{\sqrt{1 - (0.85)^2}} = 8.08 \times 10^{-19} \ \text{kg} \cdot \text{m/s}\)
\(\displaystyle p = \frac{mv}{\sqrt{1-\frac{v^2}{c^2}}} = \frac{1.67 \times 10^{-27}(0.85)(299792458)}{\sqrt{1 - (0.85)^2}} = 8.08 \times 10^{-19} \ \text{kg} \cdot \text{m/s}\)