A can do a piece of work in 10 days and B in 12 days. Find how much time it will take to complete the work if b leaves two days before scheduled completion of work? what does scheduled means ? 5.45 days no of days Combined work ?
This, as I read it, would be the problem you initially solved, when you said
If a & b work together then it is taking 5.45 days .
they are working together for 3.45 days
11/60 * 3.45 days = 0.6325 of whole work done
A is doing rest of the work by himself
Per day work = 6/60 =0.1
1 - 0.6325= 0. 3675 of work still left
0. 3675 / 0.1 = 3.675 days ( A alone)
Total= 7.125 days
Is it right?
This assumes that the "scheduled completion" is when they
expected to finish if both continued working. You solved something like t/10 + t/12 = 1, so 6t + 5t = 60 and t = 60/11 = 5.45... days for the planned project, so that 2 days before that would be 3.45... or 38/11 days. (The actual solution, without rounding, is that A works alone for 3 2/3 days, for a total of 235/33 = 7 4/33 days.
Really, I think this version of the problem is poorly stated, because we don't really know what the schedule was! We only know when they would have finished, which may have been before or after the scheduled time. I dislike unstated assumptions.
Can you check q45 post its unsolved still . the question is right i have checked it .
No, that problem is too complicated for me to care about. I did search and found someone else's solution, which confirmed that even when done in a relatively thoughtful way, it is still ugly. It also is poorly stated, though you appear to be interpreting it as intended.
Incidentally, I am not very pleased with your titles, which give no clue as to the content, so you expect others to remember which problem is #45. I'm only guessing which one you mean, and will check later. And you never even said what "T&W" means; I have to guess it is "time and work", or something like that. I also never use "P&C" as a term, but say what I mean. Your style implies disrespect.
