The angle of elevation of a wireless telegraph tower is observed

[Stein]

Application of Double Angles (Addition Formulas): The angle of elevation of a wireless telegraph tower is observed from a point on the horizontal plain (plane?) on which it stands. At a point "a" nearer the angle of elevation is the compliment of the former. At a point "b" nearer still, the angle of elevation is double the first. Show that the height of the tower is:
h= [(a+b)^2 - (a/2)^2]^(1/2)

Please!!! Anyone. I need a detailed solution. Thanks

 

[Deleted member 4993]

The angle of elevation of a wireless telegraph tower is observed from a point on the horizontal plain (plane?) on which it stands. At a point "a" nearer the angle of elevation is the compliment of the former. At a point "b" nearer still, the angle of elevation is double the first. Show that the height of the tower is:
h= [(a+b)^2 - (a/2)^2]^(1/2)


Please!!! Anyone. I need a detailed solution. Thanks

Start with drawing a sketch of the situation. Draw the three points and the angle elevations of the top of the tower. Then use "tangent angle" equations.

Please share your work with us ...

If you are stuck at the beginning tell us and we'll start with the definitions.

You need to read the rules of this forum. Please read the post titled "Read before Posting" at the following URL:

http://www.freemathhelp.com/forum/th...Before-Posting

 

[stapel]

Application of Double Angles (Addition Formulas): The angle of elevation of a wireless telegraph tower is observed from a point on the horizontal plain (plane?) on which it stands. At a point "a" nearer the angle of elevation is the compliment of the former. At a point "b" nearer still, the angle of elevation is double the first. Show that the height of the tower is:
h= [(a+b)^2 - (a/2)^2]^(1/2)

I need a detailed solution.

Why? Has your class not covered this material? If not, then what you need is a complete lesson. If so, then you already have loads of "detailed solutions" in your textbook and in your class notes.

Please reply with clarification. Do you need lesson links, so you can learn this material? Or are you having trouble somewhere in the middle? If the latter, by the way, please include all of your efforts so far. Thank you!

 

[Stein]

i can't picture out the drawing, Mr. Stapel. I found it hard to understand the problem itself. maybe you can show me somehow what the drawing looks like? so that i can try if i could solve the problem by myself.

 

[stapel]

The angle of elevation of a wireless telegraph tower is observed from a point on the horizontal plain (plane?) on which it stands.

The terrain is a flat plain, maybe a field that's been graded flat; in your right triangle, it'll be the base. The tower is vertical; in your triangle, it'll be the height line. The line of sight from the feet of the observer to the top of the tower will be the hypotenuse.

As for the rest, I take the meaning to be as follows:

Call the original position point "c"; call the point at the base of the tower "d". At a point "a", which is nearer to the base of the tower than was "c", the measure of the angle of elevation is the compliment of the measure of the former (that is, the original) angle. At a point "b", which is nearer stillto the base of the tower than was "a", the measure of the angle of elevation is double the measure of the first (that is, the original) angle.

Draw the two additional slanty lines, as indicated by "a" and "b" between "c" and "d".

 

[Stein]

is my drawing correct? if yes, what will i do next? Please guide me, Mr.Stapel.