Trig Equation!

[kinuel8091]

Solve the equation, where 0° ≤ x < 360°. Round approximate solutions to the nearest tenth of a degree.
Is this right?
3-7sin (x)=7sin (x)+2
-7sin(x)-7sin(x)=2-3
-14sin(x)=-1
sin(x)=-1/-14
sin(x)=1/14
x=arcsine 1/14
So, i used a calculator, the result was 4.096043758
x= [what should I put here]

 

[daon2]

That depends on your professor. I, personally, would prefer the exact answer \(\displaystyle x=\sin^{-1}(1/14)\). Keep in mind that there are two such angles however. They are:

\(\displaystyle x=\sin^{-1}(1/14)\) and \(\displaystyle x=180^o - \sin^{-1}(1/14)\)

 

[kinuel8091]

that depends on your professor. I, personally, would prefer the exact answer \(\displaystyle x=\sin^{-1}(1/14)\). Keep in mind that there are two such angles however. They are:

\(\displaystyle x=\sin^{-1}(1/14)\) and \(\displaystyle x=180^o - \sin^{-1}(1/14)\)

thankssss! =))