trig equation

may2012

New member
Joined
Sep 22, 2013
Messages
1
need some help with the trig equation:

2√3 sin(3x)=3

hope someone can help me :)
 
need some help with the trig equation:
2√3 sin(3x)=3
Recall that \(\displaystyle \dfrac{3}{{2\sqrt 3 }} = \dfrac{{\sqrt 3 }}{2}\).

Now if \(\displaystyle - \pi < t \le \pi \;\& \;\sin (t) = \dfrac{{\sqrt 3 }}{2}\) what is \(\displaystyle t \).

Now you show some effort. Post your work.
 
Top