trig. help needed

[curlyblueeyes12]

I am solving for radians with 0 less than or equal to x and 2pi is greater than or equal to x

2-csc x = 7

 

[stapel]

Naturally, you've already done the basic algebra, subtracting the 2 from both sides and dividing through by -1. And... then what?

Please be specific, listing all of the steps you have tried and stating clearly where you are having difficulty. Thank you.

Eliz.

 

[curlyblueeyes12]

2-csc x =7

1. -csc x = 5
2. csc x = -5
This is where I am unsure
- do I write the equation: 1/sin = 5
1= sin 5
1/5 = sin
And if I do it this way how do I find all of the places where sin = 1/5 between 0 and 2pi radians

 

[stapel]

Why did your variable disappear? (Without a variable, what would one solve for?)

Eliz.