Trig problems

[Kerriganb]

I can't figure out how to do this. I worked it out but my answers weren't in the answer choice. Can you help me? The problem is sinxcosx/1-cos^2x. I got pi/2, pi, pi/4, and 5pi/4

 

[mmm4444bot]

Can you help me?

I worked it out

We can help, if you follow our guidelines. Please click HERE, to read the main points.

Please include some of your work, so that we may see what you're doing.

The problem is sinxcosx/(1-cos^2x)

That is not a problem; that is only an expression.

Problems come with instructions. Can you post the entire exercise?

We need to type grouping symbols around multi-term denominators, as shown in red above.

I got pi/2, pi, pi/4, and 5pi/4

When x = pi/2, the given expression equals zero

When x = pi, the expression is not defined

When x = pi/4 or 5pi/4, the expression equals one

 

[MarkFL]

You gave an expression, not an equation. The best that can be done with the given expression (assuming it is \(\displaystyle \dfrac{\sin(x)\cos(x)}{1-\cos^2(x)}\)) is to simplify using a Pythagorean identity on the denominator, then reduce.